63x=16x^2-20

Solution for 63x=16x^2-20 equation:

63x=16x^2-20

We move all terms to the left:

63x-(16x^2-20)=0

We get rid of parentheses

-16x^2+63x+20=0

a = -16; b = 63; c = +20;
Δ = b2-4ac
Δ = 632-4·(-16)·20
Δ = 5249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{5249}}{2*-16}=\frac{-63-\sqrt{5249}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{5249}}{2*-16}=\frac{-63+\sqrt{5249}}{-32}
$